y=(y^2)/3

Solution for y=(y^2)/3 equation:

y=(y^2)/3

We move all terms to the left:

y-((y^2)/3)=0

We get rid of parentheses

-y^2/3+y=0

We multiply all the terms by the denominator


-y^2+y*3=0

We add all the numbers together, and all the variables

-1y^2+y*3=0

Wy multiply elements

-1y^2+3y=0

a = -1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-1)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-1}=\frac{-6}{-2}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-1}=\frac{0}{-2}
=0
$